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Antipode of Diego de Almagro

Diego de Almagro, Atacama, Chile is located at 26.390220° S, 70.045560° W.

Its antipode, the point directly opposite across Earth's centre, is at 26.390220° N, 109.954440° E.

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Red pin: the starting city. Blue pin: its exact antipode. Gold dots: nearby reference cities. Use the buttons above to view either side of Earth.

Nearest cities to the antipode of Diego de Almagro

The antipode is a calculated point, not a place in the database. The cities below are the nearest database reference cities to that point, not necessarily at it. Distances are straight-line spherical surface distances, not driving distances. This page does not say whether the point is land or ocean.

RankCityCountryPopulationDistance to antipode (km / mi)
1Shuangjiang
Find antipode of Shuangjiang
China8,32035.5 km / 22.1 mi
2Gantang
Find antipode of Gantang
China24,00040.6 km / 25.2 mi
3Hongzhou
Find antipode of Hongzhou
China21,29361.8 km / 38.4 mi
4Deshun
Find antipode of Deshun
China11,16667.3 km / 41.8 mi
5Wugang
Find antipode of Wugang
China132,45777.1 km / 47.9 mi
6Zhongchao
Find antipode of Zhongchao
China22,12978.4 km / 48.7 mi
7Hongjiang
Find antipode of Hongjiang
China476,00080.1 km / 49.8 mi
8Leidong
Find antipode of Leidong
China9,18881.0 km / 50.3 mi
9Shuikou
Find antipode of Shuikou
China26,82783.1 km / 51.7 mi
10Liping
Find antipode of Liping
China82,71083.9 km / 52.1 mi