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Antipode of Lumaco

Lumaco, Araucania, Chile is located at 38.164850° S, 72.905510° W.

Its antipode, the point directly opposite across Earth's centre, is at 38.164850° N, 107.094490° E.

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Red pin: the starting city. Blue pin: its exact antipode. Gold dots: nearby reference cities. Use the buttons above to view either side of Earth.

Nearest cities to the antipode of Lumaco

The antipode is a calculated point, not a place in the database. The cities below are the nearest database reference cities to that point, not necessarily at it. Distances are straight-line spherical surface distances, not driving distances. This page does not say whether the point is land or ocean.

RankCityCountryPopulationDistance to antipode (km / mi)
1Ningdong
Find antipode of Ningdong
China48,58744.5 km / 27.7 mi
2Linhe
Find antipode of Linhe
China16,72365.8 km / 40.9 mi
3Dongta
Find antipode of Dongta
China22,04066.3 km / 41.2 mi
4Lingwu
Find antipode of Lingwu
China52,86366.3 km / 41.2 mi
5Lingwu Nongchang
Find antipode of Lingwu Nongchang
China9,94969.6 km / 43.2 mi
6Jingui
Find antipode of Jingui
China29,79669.9 km / 43.4 mi
7Wutongshu
Find antipode of Wutongshu
China20,50670.9 km / 44.1 mi
8Chongxing
Find antipode of Chongxing
China41,21271.0 km / 44.1 mi
9Haojiaqiao
Find antipode of Haojiaqiao
China32,50772.9 km / 45.3 mi
10Yanghe
Find antipode of Yanghe
China67,90175.0 km / 46.6 mi