Antipode of Norberto de la Riestra

Norberto de la Riestra, Buenos Aires, Argentina is located at 35.273330° S, 59.775550° W.

Its antipode, the point directly opposite across Earth's centre, is at 35.273330° N, 120.224450° E.

View the Norberto de la Riestra city page

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Red pin: the starting city. Blue pin: its exact antipode. Gold dots: nearby reference cities. Use the buttons above to view either side of Earth.

Nearest cities to the antipode of Norberto de la Riestra

The antipode is a calculated point, not a place in the database. The cities below are the nearest database reference cities to that point, not necessarily at it. Distances are straight-line spherical surface distances, not driving distances. This page does not say whether the point is land or ocean.

Rank	City	Country	Population	Distance to antipode (km / mi)
1	Rizhao Find antipode of Rizhao	China	661,943	65.0 km / 40.4 mi
2	Heshan Find antipode of Heshan	China	28,784	70.5 km / 43.8 mi
3	Yinzhu Find antipode of Yinzhu	China	75,656	71.0 km / 44.1 mi
4	Taoluo Find antipode of Taoluo	China	61,852	77.5 km / 48.2 mi
5	Nanhu Find antipode of Nanhu	China	61,034	83.1 km / 51.7 mi
6	Taolin Find antipode of Taolin	China	31,795	85.6 km / 53.2 mi
7	Qingdao Find antipode of Qingdao	China	7,172,451	89.1 km / 55.4 mi
8	Chentuan Find antipode of Chentuan	China	24,706	90.5 km / 56.3 mi
9	Xihu Find antipode of Xihu	China	29,978	91.7 km / 57.0 mi
10	Linjiacun Find antipode of Linjiacun	China	88,509	95.5 km / 59.3 mi