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Antipode of San Antonio

San Antonio, Moquegua Department, Peru is located at 17.217180° S, 70.925930° W.

Its antipode, the point directly opposite across Earth's centre, is at 17.217180° N, 109.074070° E.

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Red pin: the starting city. Blue pin: its exact antipode. Gold dots: nearby reference cities. Use the buttons above to view either side of Earth.

Nearest cities to the antipode of San Antonio

The antipode is a calculated point, not a place in the database. The cities below are the nearest database reference cities to that point, not necessarily at it. Distances are straight-line spherical surface distances, not driving distances. This page does not say whether the point is land or ocean.

RankCityCountryPopulationDistance to antipode (km / mi)
1Sanya
Find antipode of Sanya
China1,031,396124.2 km / 77.2 mi
2Lăng Cô
Find antipode of Lăng Cô
Vietnam10,810151.8 km / 94.3 mi
3An Hải
Find antipode of An Hải
Vietnam82,635156.2 km / 97.0 mi
4Sơn Trà
Find antipode of Sơn Trà
Vietnam86,890156.8 km / 97.4 mi
5Da Nang
Find antipode of Da Nang
Vietnam1,276,000156.8 km / 97.5 mi
6Thanh Khê
Find antipode of Thanh Khê
Vietnam201,240158.4 km / 98.5 mi
7Hòa Cường
Find antipode of Hòa Cường
Vietnam119,363161.5 km / 100.3 mi
8Cẩm Lệ
Find antipode of Cẩm Lệ
Vietnam78,837162.4 km / 100.9 mi
9Tra Que Vegetable Village
Find antipode of Tra Que Vegetable Village
Vietnam10,000165.9 km / 103.1 mi
10Hoi An
Find antipode of Hoi An
Vietnam32,757168.3 km / 104.6 mi