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Antipode of San Fernando

San Fernando, Bicol Region, Philippines is located at 13.565600° N, 123.145300° E.

Its antipode, the point directly opposite across Earth's centre, is at 13.565600° S, 56.854700° W.

View the San Fernando city page

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Red pin: the starting city. Blue pin: its exact antipode. Gold dots: nearby reference cities. Use the buttons above to view either side of Earth.

Nearest cities to the antipode of San Fernando

The antipode is a calculated point, not a place in the database. The cities below are the nearest database reference cities to that point, not necessarily at it. Distances are straight-line spherical surface distances, not driving distances. This page does not say whether the point is land or ocean.

RankCityCountryPopulationDistance to antipode (km / mi)
1São José do Rio Claro
Find antipode of São José do Rio Claro
Brazil14,66219.6 km / 12.2 mi
2Nova Maringá
Find antipode of Nova Maringá
Brazil5,77564.5 km / 40.1 mi
3Nova Mutum
Find antipode of Nova Mutum
Brazil46,81388.4 km / 55.0 mi
4Arenápolis
Find antipode of Arenápolis
Brazil10,74798.4 km / 61.1 mi
5Nortelândia
Find antipode of Nortelândia
Brazil5,93599.0 km / 61.5 mi
6Tapurah
Find antipode of Tapurah
Brazil15,27299.2 km / 61.7 mi
7Diamantino
Find antipode of Diamantino
Brazil22,479103.6 km / 64.4 mi
8Campo Novo do Parecis
Find antipode of Campo Novo do Parecis
Brazil36,143112.8 km / 70.1 mi
9Alto Paraguai
Find antipode of Alto Paraguai
Brazil7,717112.8 km / 70.1 mi
10Lucas do Rio Verde
Find antipode of Lucas do Rio Verde
Brazil92,256115.6 km / 71.8 mi