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Antipode of San Jacinto

San Jacinto, Bicol Region, Philippines is located at 12.567700° N, 123.733700° E.

Its antipode, the point directly opposite across Earth's centre, is at 12.567700° S, 56.266300° W.

View the San Jacinto city page

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Red pin: the starting city. Blue pin: its exact antipode. Gold dots: nearby reference cities. Use the buttons above to view either side of Earth.

Nearest cities to the antipode of San Jacinto

The antipode is a calculated point, not a place in the database. The cities below are the nearest database reference cities to that point, not necessarily at it. Distances are straight-line spherical surface distances, not driving distances. This page does not say whether the point is land or ocean.

RankCityCountryPopulationDistance to antipode (km / mi)
1Tapurah
Find antipode of Tapurah
Brazil15,27232.8 km / 20.4 mi
2Ipiranga do Norte
Find antipode of Ipiranga do Norte
Brazil8,40938.4 km / 23.9 mi
3Sorriso
Find antipode of Sorriso
Brazil124,66560.3 km / 37.5 mi
4Lucas do Rio Verde
Find antipode of Lucas do Rio Verde
Brazil92,25667.7 km / 42.1 mi
5Nova Maringá
Find antipode of Nova Maringá
Brazil5,775101.3 km / 63.0 mi
6Vera
Find antipode of Vera
Brazil13,389107.1 km / 66.6 mi
7São José do Rio Claro
Find antipode of São José do Rio Claro
Brazil14,662109.5 km / 68.0 mi
8Sinop
Find antipode of Sinop
Brazil223,780114.1 km / 70.9 mi
9Nova Ubiratã
Find antipode of Nova Ubiratã
Brazil12,108121.3 km / 75.3 mi
10Santa Carmem
Find antipode of Santa Carmem
Brazil5,677125.9 km / 78.3 mi