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Antipode of San Narciso

San Narciso, Central Luzon, Philippines is located at 15.014300° N, 120.080300° E.

Its antipode, the point directly opposite across Earth's centre, is at 15.014300° S, 59.919700° W.

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Red pin: the starting city. Blue pin: its exact antipode. Gold dots: nearby reference cities. Use the buttons above to view either side of Earth.

Nearest cities to the antipode of San Narciso

The antipode is a calculated point, not a place in the database. The cities below are the nearest database reference cities to that point, not necessarily at it. Distances are straight-line spherical surface distances, not driving distances. This page does not say whether the point is land or ocean.

RankCityCountryPopulationDistance to antipode (km / mi)
1Vila Bela da Santíssima Trindade
Find antipode of Vila Bela da Santíssima Trindade
Brazil17,3843.4 km / 2.1 mi
2Pontes e Lacerda
Find antipode of Pontes e Lacerda
Brazil45,77467.0 km / 41.6 mi
3Nova Lacerda
Find antipode of Nova Lacerda
Brazil6,96568.6 km / 42.6 mi
4Jauru
Find antipode of Jauru
Brazil8,076118.8 km / 73.8 mi
5Campos de Júlio
Find antipode of Campos de Júlio
Brazil9,608149.3 km / 92.8 mi
6Comodoro
Find antipode of Comodoro
Brazil18,461150.9 km / 93.8 mi
7Araputanga
Find antipode of Araputanga
Brazil14,854175.6 km / 109.1 mi
8Cabixi
Find antipode of Cabixi
Brazil5,351182.0 km / 113.1 mi
9Porto Esperidião
Find antipode of Porto Esperidião
Brazil10,167182.1 km / 113.2 mi
10San Ignacio de Velasco
Find antipode of San Ignacio de Velasco
Bolivia23,569188.4 km / 117.1 mi