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Antipode of Tinyahuarco

Tinyahuarco, Pasco, Peru is located at 10.767710° S, 76.275230° W.

Its antipode, the point directly opposite across Earth's centre, is at 10.767710° N, 103.724770° E.

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Red pin: the starting city. Blue pin: its exact antipode. Gold dots: nearby reference cities. Use the buttons above to view either side of Earth.

Nearest cities to the antipode of Tinyahuarco

The antipode is a calculated point, not a place in the database. The cities below are the nearest database reference cities to that point, not necessarily at it. Distances are straight-line spherical surface distances, not driving distances. This page does not say whether the point is land or ocean.

RankCityCountryPopulationDistance to antipode (km / mi)
1Andoung Thma
Find antipode of Andoung Thma
Cambodia6,83313.4 km / 8.3 mi
2Ream
Find antipode of Ream
Cambodia10,33022.0 km / 13.7 mi
3Sihanoukville
Find antipode of Sihanoukville
Cambodia73,03627.7 km / 17.2 mi
4Kampot
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Cambodia22,69152.9 km / 32.9 mi
5Phú Quốc
Find antipode of Phú Quốc
Vietnam179,48061.9 km / 38.5 mi
6Koun Sat
Find antipode of Koun Sat
Cambodia9,27763.4 km / 39.4 mi
7Ou Krasar
Find antipode of Ou Krasar
Cambodia7,40066.0 km / 41.0 mi
8Phu Quoc
Find antipode of Phu Quoc
Vietnam294,41966.2 km / 41.1 mi
9Dương Đông
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Vietnam15,00066.4 km / 41.2 mi
10L’ang
Find antipode of L’ang
Cambodia6,77267.9 km / 42.2 mi